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Question
If T is the half-life of radioactive material, then the fraction that would remain after a time `"T"/2` is:
Options
`1/2`
`3/4`
`1/sqrt2`
`(sqrt2 - 1)/sqrt2`
MCQ
Solution
`1/sqrt2`
Explanation:
Fraction remains after n half lives
`"N"/"N"_0 = (1/2)^"n" = (1/2)^("t"//"T")`
∴ `"N"/"N"_0 = (1/2)^((T//2)/"T")`
= `(1/2)^(1//2)`
= `1/sqrt2`
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Radioactivity
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