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If tan α = k cot β, then αβαβcos(α-β)cos(α+β) is equal to ______. -

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Question

If tan α = k cot β, then `(cos(α - β))/(cos(α + β))` is equal to ______.

Options

  • `(1 + k)/(1 - k)`

  • `(1 - k)/(1 + k)`

  • `(k + 1)/(k - 1)`

  • `(k - 1)/(k + 1)`

MCQ
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Solution

If tan α = k cot β, then `(cos(α - β))/(cos(α + β))` is equal to `underlinebb((1 + k)/(1 - k))`.

Explanation:

∵ tan α = k cot β or tan α tan β = k

Now, `(cos(α - β))/(cos(α + β))`

= `(cos α cos β + sin α sin β)/(cos α cos β - sin α sin β)`

= `(1 + tan α tan β)/(1 - tan α tan β)`

= `(1 + k)/(1 - k)`

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Trigonometric Functions of Sum and Difference of Angles
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