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Question
If the adiabatic ratio for a gas is 5/3, find the molar specific heat capacity of the gas at (i) constant volume (ii) constant pressure.
Numerical
Solution
Data: γ = `5/3`, R = 8.314 J/mol.K
(i) γ = `C_P/C_V`
= `(C_V + R)/(C_V)`
= `1 + R/C_V`
∴ γ − 1 = `R/C_V`
∴ `C_V = R/(γ - 1)`
= `(8.314)/(5/3 -1)`
= `8.314/(2/3)`
= 12.47 J/mol.K
This is the required quantity.
(ii) `C_p = γC_V`
= `(5/3) (12.47)`
= 20.78 Jmol.K
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First Law of Thermodynamics
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