Advertisements
Advertisements
Question
If the angle of dip at places A and Bare 30° and 45° respectively, then the ratio of horizontal component of earth's magnetic field at A to that at B will be
`[sin 45^circ = cos 45^circ = 1/sqrt2, sin pi/6 = 1/2, cos pi/6 = sqrt3/2]`
Options
`sqrt2 : 1`
`1 : sqrt2`
`sqrt3 : sqrt2`
`sqrt2 : sqrt3`
MCQ
Solution
`sqrt3 : sqrt2`
Explanation:
The horizontal component of earth's magnetic field,
H = B cos δ
At place A,
HA = B cos δA
= B cos 30° = `(sqrt3"B")/2`
At place B,
HB = B cos δB
= B cos 45°
= `"B"/sqrt2`
The ratio of HA : HB becomes,
`"H"_"A"/"H"_"B" = (sqrt3"B")/2 xx sqrt2/"B" = sqrt3/sqrt2`
shaalaa.com
Torque Acting on a Magnetic Dipole in a Uniform Magnetic Field
Is there an error in this question or solution?
