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If the edge of a body-centred unit cell is 360 pm, what will be the approximate radius of the atom present in it? (in pm) -

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Question

If the edge of a body-centred unit cell is 360 pm, what will be the approximate radius of the atom present in it? (in pm)

Options

  • 311.4

  • 155.7

  • 173.0

  • 180.0

MCQ

Solution

155.7

Explanation:

For bcc unit cell, radius (r) of atom

= `sqrt3/4 "a"`

= `sqrt3/4 xx 360`

= 155.7 pm

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