Question

If the end correction of an open pipe is 0.8 cm, then the inner radius of that pipe will be ______.

Options

• `1/3`cm

• `2/3`cm

• `3/2`cm

• 0.2 cm

Answer 1

If the end correction of an open pipe is 0.8 cm, then the inner radius of that pipe will be `underlinebb(2/3"cm")`.

Explanation:

The relation between end correction (Δℓ) and inner radius of the organ pipe (r) is given by

Δl = 1.2 × r

∴ r = `(Delta"l")/1.2=0.8/1.2`    [∵ Δl = 0.8]

= `2/3`cm