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If the equation x2 – (2 + m)x + (–m2 – 4m – 4) = 0 has coincident roots, then: -

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Question

If the equation x2 – (2 + m)x + (–m2 – 4m – 4) = 0 has coincident roots, then:

Options

  • m = 0, m = 1

  • m = 2, m = 2

  • m = –2, m = –2

  • m = 6, m = 1

MCQ

Solution

m = –2, m = –2

Explanation:

For coincident roots, D = 0

⇒ [– (2 + m)]2 – 4 × 1 × (–m2 – 4m – 4) = 0

⇒ (2 + m)2 + 4(m2 + 4m + 4) = 0

⇒ (2 + m)2 + 4(m + 2)2 = 0

⇒ 5(2 + m)2 = 0

⇒ (2 + m)2 = 0

⇒ m = –2

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