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Question
If the fines given by `(x - 1)/(2lambda) = (y - 1)/(- 5) = (z - 1)/2` and `(x + 2)/lambda = (y + 3)/lambda = (z + 5)/1` are parallel, then the value of λ is ______.
Options
`2/5`
`- 5/2`
`- 2/5`
`5/2`
MCQ
Solution
If the fines given by `(x - 1)/(2lambda) = (y - 1)/(- 5) = (z - 1)/2` and `(x + 2)/lambda = (y + 3)/lambda = (z + 5)/1` are parallel, then the value of λ is `underline(- 5/2)`.
Explanation:
Given, lines
`(x - 1)/(2lambda) = (y - 1)/(- 5) = (z - 1)/2`
and `(x + 2)/lambda = (y + 3)/lambda = (z + 5)/1` are parallel
`therefore (2lambda)/lambda = (- 5)/lambda = 2/1`
`=> 2 = (- 5)/lambda = 2 = lambda = - 5//2`
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