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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 10

If the function f is defined by f(x) = {x+2;x>12;-1≤x≤1x-1;-3<x<-1 find the value of f(2) + f(– 2) - Mathematics

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Question

If the function f is defined by f(x) = `{{:(x + 2";", x > 1),(2";", -1 ≤ x ≤ 1),(x - 1";", -3 < x < -1):}` find the value of f(2) + f(– 2)

Sum

Solution

f(x) = x + 2 when x = {2, 3, 4, ……}

f(x) = 2

f(x) = x – 1 when x = {– 2}

f(x) = x + 2

f(2) = 2 + 2 = 4

f(x) = x – 1

f(– 2) = – 2 – 1 = – 3

f(2) + f(– 2) = 4 – 3

= 1

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Special Cases of Functions
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Chapter 1: Relations and Functions - Exercise 1.4 [Page 25]

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Samacheer Kalvi Mathematics [English] Class 10 SSLC TN Board
Chapter 1 Relations and Functions
Exercise 1.4 | Q 9. (iv) | Page 25
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