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Question
If the kinetic energy of a free electron double, its de-Broglie wavelength changes by the factor ______.
Options
1/2
`1//sqrt2`
`sqrt2`
2
MCQ
Fill in the Blanks
Solution
If the kinetic energy of a free electron doubles, its de-Broglie wavelength changes by the factor `underline(1//sqrt2)`.
Explanation:
Let λ be de-Broglie wavelength of electron, when its kinetic energy is E. Then,
`lambda = "h"/sqrt(2"mE")`
Let λ′ be de-Broglie wavelength of electron, when its kinetic energy is doubled. Then,
`lambda' = "h"/sqrt("2m" xx "2E")`
`= 1/sqrt2 xx "h"/sqrt"2mE" = 1/sqrt2 lambda`
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