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Question
If the median of 33, 28, 20, 25, 34, x is 29, find the maximum possible value of x.
Solution
There are 6 observations i.e. even no. of observations.
So, median will be:
`(("3rd observation + 4th observation"))/2`
Arranging in increasing order:
20, 25, 28, x, 33, 34
If we put any other number at 4th position the n, we will not get the median = 29
So, `(28 + x)/2` = 29
28 + x = 58
x = 58 − 28
= 30
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