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Question
If the p.d.f of a c.r.v. X is
f(x) = `{:("K.e"^(-thetax)";", theta > 0"," 0 ≤ x < oo),(0";", "otherwise"):}`
Then, K = ______.
Options
`theta/3`
`theta/2`
θ
2θ
MCQ
Fill in the Blanks
Solution
If the p.d.f of a c.r.v. X is
f(x) = `{:("K.e"^(-thetax)";", theta > 0"," 0 ≤ x < oo),(0";", "otherwise"):}`
Then, K = θ.
Explanation:
Since, f(x) is the p.d.f. of X
∴ `int_-oo^oo "f"(x) "d"x` = 1
∴ `int_0^oo "K.e"^(-thetax) "d"x` = 1
∴ `"K"["e"^(-thetax)/(-theta)]_0^oo` = 1
⇒ `- "K"/theta [1/"e"^(thetax)]_0^oo` = 1
⇒ `- "K"/theta [1/"e"^oo - 1/"e"^0]` = 1
⇒ `- "K"/theta [1/oo - 1/1]` = 1
⇒ `"K"/theta` = 1
⇒ K = θ
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