Question

If the potential barrier across a p-n junction is 0.6 V. Then the electric field intensity, in the depletion region having the width of 6 × 10^-6m, will be ______ × 10⁵ N/C.

Options

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Answer 1

If the potential barrier across a p-n junction is 0.6 V. Then the electric field intensity, in the depletion region having the width of 6 × 10^-6m, will be 1 × 10⁵ N/C.

Explanation:

Electric field is given as, E =`"V"/"d"`

= `"Potential barrier across junction"/"Width of depletion layer"`

= `(0.6"V")/(6xx10^-6"m")`

= 1 × 10⁵ V/m

= 1 × 10⁵ N/C.