Question

If the potential difference used to accelerate electrons is doubled, by what factor does the de-Broglie wavelength associated with the electrons change?

Options

• Wavelength is increased to `1/2` times

• Wavelength is decreased to `1/sqrt2` times

• Wavelength is increased to `1/sqrt2` times

• Wavelength is decreased to `1/3` times

Answer 1

Wavelength is decreased to `1/sqrt2` times

Explanation:

The de Broglie wavelength is given by

`lambda ("in nm") = 1.23/sqrt"V"`

Hence in become `1/sqrt2` times