Question

If the refractive index of a material of equilateral prism is `sqrt(3)` then angle of minimum deviation of prism

Options

• 30°

• 45°

• 60°

• 75°

Answer 1

60°

Explanation:

A = 60°, `mu = sqrt(3)`, Sm = ?

`mu = ((sin(A + Sm))/2)/(sin A/2)`

= `(sin(A + Sm))/2`

= `mu Sin  A/2`

= `sqrt(3 sin 30^circ)`

= `sqrt(3)/2`

= sin 60° Sm

= 120° – A

= 120° – 60°

= 60°