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If the roots of px2 + qx + 2 = 0 are reciprocal of each other, then: -

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Question

If the roots of px2 + qx + 2 = 0 are reciprocal of each other, then:

Options

  • p = 0

  • p = −2

  • p = ±2

  • p = 2

MCQ

Solution

p = 2

Explanation:

Here α = `1/β`

∴ αβ = 1

⇒ `2/"p"` = 1

∴ p = 2

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