English

If the value of Ksp for Hg2Cl2 (s) is X then the value of X will be ____ where pX = - log X. Given: HgA2ClA2+2eA−⟶2Hg(l)+2ClA−, E° = 0.27 V HgA2++2eA−⟶2Hg(l) E° = 0.81 V -

Advertisements
Advertisements

Question

If the value of Ksp for Hg2Cl2 (s) is X then the value of X will be ____ where pX = - log X.
Given:

\[\ce{Hg2Cl2 + 2e- -> 2Hg(l) + 2Cl-}\],  E° = 0.27 V

\[\ce{Hg+2 + 2e- -> 2Hg(l)}\]   E° = 0.81 V

Options

  • 8

  • 2

  • 6

  • 0

MCQ
Fill in the Blanks

Solution

If the value of Ksp for Hg2Cl2 (s) is X then the value of X will be 6 where pX = - log X.

Explanation:

`"E"°_("Cl"°//"Hg"_2"Cl"_2//"Hg") = "E"°_("Hg"_2^(2+)//"Hg") + 0.059/2 log "K"_"sp" ("Hg"_2"Cl"_2)`

0.27 = `0.81 + 0.06/2 log "K"_"sp"`

`0.06/2 log "K"_"sp" ("Hg"_2"Cl"_2)` = - 0.54

log Ksp (Hg2Cl2) = - 18

X = log Ksp (Hg2Cl2) = 10-18

- log X = - log Ksp (Hg2Cl2) = 18

`"pX"/3 = - 1/3 log X = 18/3 = 6`

shaalaa.com
  Is there an error in this question or solution?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×