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Question
If the value of Ksp for Hg2Cl2 (s) is X then the value of X will be ____ where pX = - log X.
Given:
\[\ce{Hg2Cl2 + 2e- -> 2Hg(l) + 2Cl-}\], E° = 0.27 V
\[\ce{Hg+2 + 2e- -> 2Hg(l)}\] E° = 0.81 V
Options
8
2
6
0
MCQ
Fill in the Blanks
Solution
If the value of Ksp for Hg2Cl2 (s) is X then the value of X will be 6 where pX = - log X.
Explanation:
`"E"°_("Cl"°//"Hg"_2"Cl"_2//"Hg") = "E"°_("Hg"_2^(2+)//"Hg") + 0.059/2 log "K"_"sp" ("Hg"_2"Cl"_2)`
0.27 = `0.81 + 0.06/2 log "K"_"sp"`
`0.06/2 log "K"_"sp" ("Hg"_2"Cl"_2)` = - 0.54
log Ksp (Hg2Cl2) = - 18
X = log Ksp (Hg2Cl2) = 10-18
- log X = - log Ksp (Hg2Cl2) = 18
`"pX"/3 = - 1/3 log X = 18/3 = 6`
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