Question

If two moles of an ideal gas at 546 K occupy a volume of 44.8 L. What is the pressure of ideal gas at 546 K? (R = 0.0821 L atm mol^-1 K^-1)

Options

• 20 atm

• 0.2 atm

• 0.5 atm

• 2.0 atm

Answer 1

2.0 atm

Explanation:

n = 2 mol, T = 546 K, V = 44.8 L, R= 0.0821 L atm mol^-1 K^-1, P = ?

According to ideal gas equation,

PV = nRT

∴ P = `"nRT"/"V" = (2 xx 0.0821 xx 546)/44.8` = 2.0 atm