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If two resistors of resistances R1 = (4 ± 0.5) Ω and R2 = (16 ± 0.5) Ω are connected in series. The eqivalent resistance with the limits of percentage error is ______. -

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Question

If two resistors of resistances R= (4 ± 0.5) Ω and R2 = (16 ± 0.5) Ω are connected in series. The eqivalent resistance with the limits of percentage error is ______.

Options

  • (20 ± 1%) Ω

  • (20 ± 5%) Ω

  • (20 ± 0.25 %) Ω

  • (20 ± 0.5 %) Ω

MCQ
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Solution

If two resistors of resistances R= (4 ± 0.5) Ω and R2 = (16 ± 0.5) Ω are connected in series. The eqivalent resistance with the limits of percentage error is (20 ± 1%) Ω.

Explanation:

In series combination, equivalent resistance Req = R1 + R2

Given, R1 = (r1 + Δr1) = (4 ± 0.5) Ω

R2(r + Δr2) = (16 ±  0.5) Ω 

∴ Req = (r1 + r2) ± (Δr1 + Δr2)

= (4 + 16) ± (0.5 + 0.5) = Ω

∴ Req = (20 ± 1%) = Ω

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