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Question
If two resistors of resistances R1 = (4 ± 0.5) Ω and R2 = (16 ± 0.5) Ω are connected in series. The eqivalent resistance with the limits of percentage error is ______.
Options
(20 ± 1%) Ω
(20 ± 5%) Ω
(20 ± 0.25 %) Ω
(20 ± 0.5 %) Ω
MCQ
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Solution
If two resistors of resistances R1 = (4 ± 0.5) Ω and R2 = (16 ± 0.5) Ω are connected in series. The eqivalent resistance with the limits of percentage error is (20 ± 1%) Ω.
Explanation:
In series combination, equivalent resistance Req = R1 + R2
Given, R1 = (r1 + Δr1) = (4 ± 0.5) Ω
R2(r + Δr2) = (16 ± 0.5) Ω
∴ Req = (r1 + r2) ± (Δr1 + Δr2)
= (4 + 16) ± (0.5 + 0.5) = Ω
∴ Req = (20 ± 1%) = Ω
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