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Question
If the volume of two cones are in the ratio 1 : 4 and their diameters are in the ratio 4 : 5, then the ratio of their heights, is
Options
1 : 5
5 : 4
5 : 16
25 : 64
Solution
The formula of the volume of a cone with base radius ‘r’ and vertical height ‘h’ is given as
Volume = `1/3 pir^2 h`
Let the volume, base radius and the height of the two cones be `V_1 , r_1,h_1` and `V_2,r_2,h2` respectively.
It is given that the ratio between the volumes of the two cones is 1 : 4.
Since only the ratio is given, to use them in our equation we introduce a constant ‘k’.
So, `V_1`= 1k
`V_2`= 4k
It is also given that the ratio between the base diameters of the two cones is 4 : 5.
Hence the ratio between the base radius will also be 4 : 5.
Again, since only the ratio is given, to use them in our equation we introduce another constant ‘p’.
So, `r_1` = 4p
`r_2`= 5p
Substituting these values in the formula for volume of cone we get,
`("Volume of cone_1") /("Volume of cone_2")=((pi)(4 p)(4 p)(h_1)(3))/((3)(pi)(5p)(5 p)(h_2))`
`V_1/V_2 = (16h_1)/(25h_2)`
`(1k)/(4k) = (16h_1)/(25h_2)`
`(h_1)/(h_2) = 25/64`
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