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Question
If x = 1, y = 2 and z = 3, find the value of x2 + y2 + 2xyz.
Solution
Given:
x =1
y = 2
z = 3
Substituting x = 1, y = 2 and z = 3 in the given equation (x2 + y2 + 2xyz):
\[\left( 1 \right)^2 + \left( 2 \right)^2 + 2\left( 1 \right)\left( 2 \right)\left( 3 \right)\]
\[ \Rightarrow 1 + 4 + 12 = 17\frac{}{}\]
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