Question

If `|(x + a, beta, y),(a, x + beta, y),(a, beta, x + y)|` = 0, then 'x' is equal to

Options

• `0, - (a + beta + y)`

• `0, (a + beta + y)`

• `1, - (a + beta + y)`

• `0,  (a^2 + beta^2 + y^2)`

Answer 1

`0, - (a + beta + y)`

Explanation:

Applying C₁ `->` C₁ + C₂ + C₃

⇒ `(x + a +  beta + y) |(1, beta, y),(1, x + beta, y),(1, beta, x + y)|` = 0

⇒ `(x + a + beta + y) . x^2` = 0

⇒ `x = 0, - (a, beta + y)`