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Question
If X ~ B(6, p) and 2·P(X = 3) = P(X = 2), then find p.
Solution
P(X = x) = nCxpxqn – x, where n = 6
∴ P(X = x) = 6Cxpxq6 – x
Given: 2·P(X = 3) = P(X = 2)
∴ 2 × 6C3p3q6 – 3 = 6C2p2q6 – 2
∴ `2 xx (6 xx 5 xx 4)/(1 xx 2 xx 3)*p^3q^3 = (6 xx 5)/(1 xx 2)p^2q^4`
∴ 40p = 15q = 15(1 – p)
∴ 40p = 15 – 15p
∴ 55p = 15
∴ p = `15/55 = 3/11`
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