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Question
If Xis a.r.v. with c.d.f F (x) and its probability distribution is given by
X = x | - 1.5 | -0.5 | 0.5 | 1.5 | 2.5 |
P(X = x) | 0.05 | 0.2 | 0.15 | 0.25 | 0.35 |
then, F(1.5) - F(- 0.5) = ?
Options
0.2
0.4
0.1
0.3
MCQ
Solution
0.4
Explanation:
Given,
X = x | - 1.5 | -0.5 | 0.5 | 1.5 | 2.5 |
P(X = x) | 0.05 | 0.2 | 0.15 | 0.25 | 0.35 |
F(X = x) = P(X ≤ x)
∴ F(1.5) = P(X ≤ 1.5)
= P(X = - 1.5) + P(X = - 0.5) + P(X = 0.5) + P(X = 1.5)
= 0.05 + 0.2 + 0.15 + 0.25 = 0.65
F(- 0.5) = P(X ≤ - 0.5)
= P(X = - 1.5) + P(X = - 0.5)
= 0.05 + 0.2 = 0.25
F(1.5) - F(- 0.5) = 0.65 - 0.25 = 0.4
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Types of Random Variables
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