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If Xis a.r.v. with c.d.f F (x) and its probability distribution is given by X = x - 1.5 -0.5 0.5 1.5 2.5 P(X = x) 0.05 0.2 0.15 0.25 0.35 then, F(1.5) - F(- 0.5) = ? -

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Question

If Xis a.r.v. with c.d.f F (x) and its probability distribution is given by

X = x - 1.5 -0.5 0.5 1.5 2.5
P(X = x) 0.05 0.2 0.15 0.25 0.35

then, F(1.5) - F(- 0.5) = ?

Options

  • 0.2

  • 0.4

  • 0.1

  • 0.3

MCQ

Solution

0.4

Explanation:

Given,

X = x - 1.5 -0.5 0.5 1.5 2.5
P(X = x) 0.05 0.2 0.15 0.25 0.35

F(X = x) = P(X ≤ x)

∴ F(1.5) = P(X ≤ 1.5)

= P(X = - 1.5) + P(X = - 0.5) + P(X = 0.5) + P(X = 1.5)

= 0.05 + 0.2 + 0.15 + 0.25 = 0.65

F(- 0.5) = P(X ≤ - 0.5)

= P(X = - 1.5) + P(X = - 0.5)

= 0.05 + 0.2 = 0.25

F(1.5) - F(- 0.5) = 0.65 - 0.25 = 0.4

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