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Question
If `"xy"^2 = "ax"^2 + "bxy" + "y"^2, "then find" "dy"/"dx"`
Options
`(2"ax" + "by" + "y"^2)/(2"xy" + "bx" + 2"y")`
`(2"ax" + "by" - "y"^2)/(2"xy" - "bx" - 2"y")`
`("ax" + "by" - "xy")/("xy" + "x"^2 + "y"^2)`
`(2"x"^2 + "axy" + "y"^2)/("x"^2 + "y"^2 + 2"xy")`
MCQ
Solution
`(2"ax" + "by" - "y"^2)/(2"xy" - "bx" - 2"y")`
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