Question

If ${\displaystyle {\text{y = a}}^{\text{x}},{\text{b}}^{2\text{x}-1},\text{then}\frac{{\text{d}}^2\text{y}}{{\text{dx}}^2}}$ is ____________.

Options

• ${\displaystyle {\text{y}}^2.{\text{log ab}}^2}$

• ${\displaystyle \text{y}.{\text{log ab}}^2}$

• ${\displaystyle \text{y}.{\left({\text{log ab}}^2\right)}^2}$

• ${\displaystyle \text{y}.{\left({\text{log a}}^2\text{b}\right)}^2}$

Answer 1

If ${\displaystyle {\text{y = a}}^{\text{x}},{\text{b}}^{2\text{x}-1},\text{then}\frac{{\text{d}}^2\text{y}}{{\text{dx}}^2}}$ is ${\displaystyle \underline{\text{y}.{\left({\text{log ab}}^2\right)}^2}}$.