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Question
If y = log (sec x + tan x), find `dy/dx`.
Sum
Solution
∵ y = log (sec x + tan x)
∴ `dy/dx = 1/(secx + tanx) xx d/dx (secx + tanx)`
= `(secx tanx + sec^2x)/(secx + tanx)`
= `(secx (tanx + secx))/((secx + tanx))`
= sec x
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Differentiation
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