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If yxxnthenxdydxxdydxy=(x+1+x2)n, then(1+x2) d2ydx2+xdydx is ____________. -

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Question

If `"y" = ("x" + sqrt(1 + "x"^2))^"n",  "then" (1 + "x"^2)  ("d"^2 "y")/"dx"^2 + "x" ("dy")/("dx")` is ____________.

Options

  • `"n"^2 "y"`

  • `-"n"^2 "y"`

  • - y

  • `2  "x"^2  "y"`

MCQ
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Solution

If `"y" = ("x" + sqrt(1 + "x"^2))^"n",  "then" (1 + "x"^2)  ("d"^2 "y")/"dx"^2 + "x" ("dy")/("dx")` is `underline("n"^2 "y")`.

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