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Question
In 2 hours, a certain current liberates 0.504 g hydrogen. How many grams of copper can be deposited by the same current flowing for the same time in a CuSO4 solution?
(Molar mass of Cu = 63.5 g mol−1, H2 = 2.0 g mol−1)
Options
63.5 g
16.0 g
31.8 g
32 g
MCQ
Solution
16.0 g
Explanation:
`"Mass of Hydrogen"/"Mass of Copper" = "Equivalent mass of hydrogen"/"Equivalent mass of copper"`
`0.504/"Mass of copper" = 1/(63.5//2)`
Amount of copper deposited = `0.504 xx 63.5/2` = 16 g
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Electrical Conductance of Solution
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