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Question
In a ΔABC, AD is the bisector of ∠A, meeting side BC at D.
If AD = 5.6 cm, BC = 6cm and BD = 3.2 cm, find AC.
Sum
Solution
We have,
In ΔABC, AD is the bisector of ∠A.
We know that, the internal bisector of an angle of a triangle divides the opposite side internally in the ratio of the containing the angle.
`therefore"AB"/"AC"="BD"/"DC"`
⇒ `5.6/"AC"=3.2/(6-3.2)` [∵ DC = BC – BD]
⇒ `5.6/"AC"=3.2/2.8`
⇒ `"AC"=(5.6xx2.8)/3.2`
= `(5.6xx7)/8=0.7xx7`
= 4.9 cm
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