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Tamil Nadu Board of Secondary EducationHSC Science Class 11

In a ∆ABC, if a = 18 cm, b = 24 cm and c = 30 cm, then show that its area is 216 sq.cm - Mathematics

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Question

In a ∆ABC, if a = 18 cm, b = 24 cm and c = 30 cm, then show that its area is 216 sq.cm

Sum

Solution

In a ∆ABC,

Given a = 18 cm, b = 24 cm and c = 30 cm

S = `("a" + "b" + "c")/2`

= `(18 + 24 + 30)/2`

= `7/2`

= 36

Area of the triangle ABC

∆ = `sqrt("s"("s" - "a")("s" - "b")("s"- "c"))`

∆ = `sqrt(36(36 - 18)(36 - 24)(36 - 30))`

∆ = `sqrt(36 xx 18 xx 12 xx 6)`

= `sqrt(6 xx 6 xx 3 xx 6 xx 2 xx 6 xx 6)`

= `sqrt(6^2 xx 6^2 xx 3 xx 2 xx 6)` 

= `sqrt(6^2 xx 6^2 xx 6^2)`

= 6 × 6 × 6

= 216 sq.cm

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Chapter 3: Trigonometry - Exercise 3.10 [Page 146]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 3 Trigonometry
Exercise 3.10 | Q 6 | Page 146

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