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Question
In a binomial distribution `B(n, p = 1/4)`, if the probability of at least one success is greater than or equal to `9/10`, then n is greater than ______.
Options
`1/(log_10 4 + log_10 3)`
`9/(log_10 4 - log_10 3)`
`4/(log_10 4 - log_10 3)`
`1/(log_10 4 - log_10 3)`
Solution
In a binomial distribution `B(n, p = 1/4)`, if the probability of at least one success is greater than or equal to `9/10`, then n is greater than `underlinebb(1/(log_10 4 - log_10 3))`
Explanation:
Given that P = `1/4` `\implies` q = `1 - 1/4 = 3/4`
and `P(x ≥ 1) ≥ 9/10 \implies 1 - P(x = 0) ≥ 9/10`
`\implies 1 - ""^nC_0 (1/4)^0 (3/4)^n ≥ 9/10`
`\implies 1 - 9/10 ≥ (3/4)^n`
`\implies (3/4)^n ≤ (1/10)`
Taking log at the base `3/4`, on both sides, we get
`n log_(3/4) ≥ log_(3/4) (1/10)`
`\implies n ≥ - log_(3/4) 10 = (- log_10 10)/(log_10 (3/4)) = (-1)/(log_10 3 - log_10 4)`
`\implies n ≥ 1/(log_10 4 - log_10 3)`