English

In a biprism experiment, the slit is illuminated by red light of wavelength 6400 A and the crosswire of eyepiece is adjusted to the centre of 3rd bright band. By using blue light it is found that 4th -

Advertisements
Advertisements

Question

In a biprism experiment, the slit is illuminated by red light of wavelength 6400 A and the crosswire of eyepiece is adjusted to the centre of 3rd bright band. By using blue light it is found that 4th bright band is at the centre of the cross wire. Calculate the wavelength of blue light.

Numerical

Solution

For bright band `x_n =(nDλ)/d` 

For red light, distance of 3rd bright band is

`x_3=(3Dλ_R)/d`

For blue light, distance of 4th bright band is

`x_4=(4Dλ_B)/d`

By condition,

(Distance of 3rd bright band of red light) = (Distance of 4th bright band of red light)

`(3Dλ_R)/d = (4Dλ_B)/d`

`3/4λ_R =λ_B`

`λ_B = 3/4xx6400`

λB = 4800 A

shaalaa.com
Diffraction of Light
  Is there an error in this question or solution?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×