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Question
In a capillary tube having area cross-section 'A' water rises to a height 'h'. If cross-sectional area is reduced to `"A"/9`, the rise of water in the capillary tube is ______.
Options
4h
3h
2h
h
MCQ
Fill in the Blanks
Solution
In a capillary tube having area cross-section 'A' water rises to a height 'h'. If cross-sectional area is reduced to `"A"/9`, the rise of water in the capillary tube is 3h.
Explanation:
From Jurin's law, h ∝ `1/"r"` or, rh = constant
`"r"_1"h"_1="r"_2"h"_2` A1 = π`"r"_1^2`
`"r"_1/"r"_2="h"_2/"h"_1` A2 = π`"r"_2^2`
3 = `"h"_2/"h"_1="h"_2/"h"_1` `(pi"r"_1^2)/9=pi"r"_2^2`
h2 = 3h1 = 3h `"r"_1^2/"r"_2^2` = 9 ⇒ `"r"_1/"r"_2` = 3h
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