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Question
In a CE transistor amplifier, the audio signal voltage across the collector resistance of2 kΩ is 2 V If the base resistance is 1 kΩ and the current amplification of the transistor is 100, the input signal voltage is
Options
0.1V
1.0V
1mV
10mV
MCQ
Solution
10mV
Explanation:
The output voltage across the load RC, V0 = ICRC = 2
The collector current IC = `2/(2 xx 10^3) = 10^-3"A"`
Current gain B = `("I"_"C")/("I"_"B") = 100`
IB = `("I"_"C")/100 = (10^-3)/100 =10^-5 "A"`
Input voltage Vi = IBRB = 1 × 103 × 10−5
= 10−2 V = 10mV
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