Question

In a class, 30% of the students offered English, 20% offered Hindi and 10% offered both. If a student is selected at random, what is the probability that he has offered English or Hindi?

Options

• `1/2`

• `3/4`

• `4/5`

• `2/5`

Answer 1

`2/5`

Explanation:

`P(E)=30/100=3/10, P(H)=20/100=1/5`

and P(E∩H)= `10/100=1/10`

P(E    H) = P(E∪H)
= P (E) + P (H) - P (E∩H)

= `(3/10+1/5+1/10)`

= `4/10=2/5`