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Question
In a class of 50 boys, 35 boys play Carrom and 20 boys play Chess then the number of boys play both games is
Options
5
30
15
10
Solution
5
Explanation;
Hint:
n(A ∪ B) = 50, n(A) = 35, n(B) = 20
n(A ∩ B) = n(A) + n(B) – n(A ∪ B)
= 35 + 20 – 50
= 5
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