Question

In a common emitter amplifier, the input resistance is 1000 Ω, the peak value of Input signal voltage is 5 mV, and β = 60. The peak value of output current is

Options

• 3 × 10^-4 A

• 0.5 × 10^-4 A

• 2 × 10^-5 A

• 1 × 10^-5 A

Answer 1

3 × 10^-4 A

Explanation:

Given, input resistance, R_i = 1000Ω,
Input voltage, V_i or V_B = 5 mV = 5 × 10^-3 V and β = 60
∴ Input or base current,

`"I"_"B"="V"_"B"/"R"_"i"=(5xx10^-3)/1000=5xx10^-6"A"`

As, `beta="I"_"C"/"I"_"B"`

⇒ l_C = β × I_B
= 60 × 5 × 10^-6
= 3 × 10^-4 A

∴ Peak value of output current, l_C = 3 × 10^-4 A