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In a first order reaction, the concentration of the reactant, decreases from 0.8 mol dm−3 to 0.4 mol dm−3 in 15 minutes. The time taken for the concentration -

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Question

In a first order reaction, the concentration of the reactant, decreases from 0.8 mol dm−3 to 0.4 mol dm−3 in 15 minutes. The time taken for the concentration to change from 0.1 mol dm−3 to 0.025 mol dm−3 is ____________.

Options

  • 60 minutes

  • 15 minutes

  • 7.5 minutes

  • 30 minutes

MCQ
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Solution

In a first order reaction, the concentration of the reactant, decreases from 0.8 mol dm−3 to 0.4 mol dm−3 in 15 minutes. The time taken for the concentration to change from 0.1 mol dm−3 to 0.025 mol dm−3 is 30 minutes.

Explanation:

Half life period `"t"_(1//2)` = 15 min.

Calculating the number of `"t"_(1//2)` required to decrease the concentration from 0.1 mol dm−3 to 0.025 mol dm−3,

\[\ce{0.1 ->[t_{{1/2}}] 0.05 ->[t_{{1/2}}] 0.025}\]

number of `"t"_(1//2)` = 2

∴ time taken = 2 × 15 = 30 min

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