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Question
In a hexagon ABCDEF, side AB is parallel to side FE and ∠B : ∠C : ∠D : ∠E = 6 : 4 : 2 : 3. Find ∠B and ∠D.
Solution
Given: Hexagon ABCDEF in which AB || EF and ∠B : ∠C : ∠D : ∠E = 6 : 4 : 2 : 3.
To find: ∠B and ∠D
Proof: No. of. sides n = 6
∴ Sum of interior angles = (n - 2) × 180°
= (6 - 2) × 180°
= 720°
∵ AB || EF (Given)
∴ ∠A + ∠F = 180°
But ∠A + ∠B + ∠C + ∠D + ∠E + ∠F = 720° (Proved)
∠B + ∠C + ∠D + ∠E + 180° = 720°
∴ ∠B + ∠C + ∠D + ∠E = 720° - 180°
Ratio = 6: 4: 2: 3
Sum of parts = 6 + 4 + 2 + 3 = 15
∴ ∠B = `6/15 xx 540 = 216^circ`
∠D = `2/15 xx 540^circ = 72^circ`
Hence ∠B = 216° ; ∠D = 72°
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