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Question
In a market survey three commodities A, B and C were considered. In finding out the index number some fixed weights were assigned to the three varieties in each of the commodities. The table below provides information regarding the consumption of three commodities according to the three varieties and also the total weight received by the commodity.
Commodity | Total weight | Total weight | ||
I | II | III | ||
A | 1 | 2 | 3 | 11 |
B | 2 | 4 | 5 | 21 |
C | 3 | 5 | 6 | 27 |
Find the weights assigned to the three varieties by using Cramer’s Rule
Solution
Let x, y and z be are consumption of three commodities A, B and C respectively.
Given that
x + 2y + 3z = 11 ........(1)
2x + 4y + 5z = 21 ........(2)
3x + 5y + 6z = 27 ........(2)
Here Δ = `|(1, 2, 3),(2, 4, 5),(3, 5, 6)|`
= 1(24 – 25) – 2(12 – 15) + 3(10 – 12)
= 1(1) 2(3) + 3(– 2)
= – 1 + 6 – 6
= – 1 ≠ 0
∴ We can apply Cramer’s Rule
Now `Delta_x = |(11, 2, 3),(21, 4, 5),(27, 5, 6)|`
= 11(24 – 25) – 2(126 – 135) + 3(105 – 108)
= 11(–1) – 2(– 9)+ 3(– 3)
= – 11 + 18 – 9
= – 2
`Delta_y = |(1, 11, 3),(2, 21, 5),(3, 27, 6)|`
= 1(126 – 135) – 11(12 – 15) + 3(54 – 63)
= 1(– 9) -11(– 3) + 3(– 9)
= – 9 + 33 – 27
= – 3
`Delta_z = |(1, 2, 11),(2, 4, 21),(3, 5, 27)|`
= 1(108 – 105) – 2(54 – 63) + 11(10 – 12)
= 1(3) – 2(– 9) + 11(– 2)
= 3 + 18 – 22
= – 1
∴ By Cramer’s Rule
x = `Delta_x/Delta = (-2)/(-1)` = 2
y = `Delta_y/Delta = (-3)/(-1)` = 3
z = `Delta_y/Delta = (-1)/(-1)` = 1
∴ (x, y, z) = (2, 3, 1)