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In an Election Between Two Candidates, One Candidate Secured 58% of the Votes Polled and Won the Election by 18, 336 Votes. Find the Total Number of Votes Polled and the Votes Secured by Each - Mathematics

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Question

In an election between two candidates, one candidate secured 58% of the votes polled and won the election by 18, 336 votes. Find the total number of votes polled and the votes secured by each candidate.

Sum

Solution

Since, winning candidate secured 58% of the votes polled.

∴ Losing candidate secured

= (100 − 58) of the votes polled

= 42% of the votes polled

Difference of votes 

= 58 − 42

= 16% of the votes polled

We are given:

16% of votes polled = 18,336

⇒ `(16)/(100)` of the votes polled = 18,336

⇒ Votes polled = `18,336 xx (100)/(16)`

⇒ Votes polled = `(18,33,600)/(16)`

⇒ Votes polled = 1,14,600

∴ Votes secured by winning candidate

= `(58)/(100) xx 1,14,600`

= 66,468

Votes secured by losing candidate

= `(42)/(100) xx 1,14,600`

= 48,132

Votes polled = 1,14,600

Votes secured by winning candidate = 66,468

Votes secured by losing candidate = 48,132

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Chapter 7: Percent and Percentage - Exercise 7 (A) [Page 82]

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Selina Concise Mathematics [English] Class 8 ICSE
Chapter 7 Percent and Percentage
Exercise 7 (A) | Q 11 | Page 82
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