Question

In an isosceles triangle one angle is 76°. If the other two angles are equal find them

Answer 1

In an isosceles triangle, angle opposite to equal sides are equal

Let the equal angles be x° and x°

In a triangle the sum of the three angles is 180°

x° + x° + 76° = 180°

x°(1 + 1) = 180° – 76° = 104°

2x = 104°

x = `(104^circ)/2` = 52°

x = 52°

∴ Other two angles are 52° and 52°.