Question

In an ore of iron, iron is present in two oxidation state Feⁿ⁺ and `"Fe"^(("n"+1)+)`. Number of `"Fe"^(("n"+1)+)` is twice the number of Feⁿ⁺. If empirical formula of ore is Fe_xO. The value of [x × 100] is ______.

Options

• 30

• 50

• 75

• 100

Answer 1

In an ore of iron, iron is present in two oxidation state Feⁿ⁺ and `"Fe"^(("n"+1)+)`. Number of `"Fe"^(("n"+1)+)` is twice the number of Feⁿ⁺. If empirical formula of ore is Fe_xO. The value of [x × 100] is 75.

Explanation:

Fe²⁺ and Fe³⁺

Number of Fe³⁺ = 2 × Number of Fe²⁺

∴ EF = \[\ce{2Fe^{3+}.Fe^{2+}O^{2-}4}\] = Fe_0.75O

Fe_xO = Fe_0.75O

x = 0.75

Value of (x × 100) = 0.75 × 100 = 75