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In CuA2++Ag⟶Cu+AgA+, oxidation half-reaction is: -

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Question

In \[\ce{Cu^{2+} + Ag -> Cu + Ag^+}\], oxidation half-reaction is:

Options

  • \[\ce{Cu^{2+} -> Cu}\]

  • \[\ce{Ag -> Ag^+}\]

  • \[\ce{Cu -> Cu^{2+}}\]

  • All of these

MCQ

Solution

\[\ce{Ag -> Ag^+}\]

Explanation:


Thus, the oxidation-half reaction is \[\ce{Ag -> Ag^+}\]

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Balancing Redox Reactions in Terms of Loss and Gain of Electrons
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