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Question
In each of the following find the values of k of which the given value is a solution of the given equation:
x2 - x(a + b) + k = 0, x = a
Solution
x2 - x(a + b) + k = 0, x = a.
Putting x = a in L.H.S. of equation
⇒ (a)2 - a(a + b) + k = 0
⇒ a2 - a2 - ab + k = 0
Hence, k = ab.
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