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Question
In ΔPQR, PQ = 10 cm, QR = 12 cm, PR = 8 cm. Find out the greatest and the smallest angle of the triangle.
Sum
Solution
In ∆PQR,
PQ = 10 cm, QR = 12 cm, PR = 8 cm ...[Given]
Since, 12 > 10 > 8
∴ QR > PQ > PR
∴ ∠QPR > ∠PRQ > PQR ...[Angle opposite to greater side is greater]
∴ In ∆PQR, ∠QPR is the greatest angle and ∠PQR is the smallest angle.
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Properties of inequalities of sides and angles of a triangle
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