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Question
In ∆PQR, PR = 8 cm, QR = 4 cm and PL = 5 cm.
Find:
(i) the area of the ∆PQR
(ii) QM.
Sum
Solution
(i) QR = base = 4 cm, PL = height = 5 cm
Area of the triangle PQR =`1/2bh`
= `1/2 xx 4 xx 5`
= 10 cm2
(ii) PR = base = 8 cm, QM = height = ?, Area = 10 cm2
Area of triangle = `1/2 xx b xx h`
10 = `1/2 xx 8 xx h`
h = `10/4 = 5/2 = 2.5`.
QM = 2.5 cm
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