Question

In the freundilch adsorption isotherm, the value of x/m is 0.4 under a pressure of 0.2 at m calculate the value of the interact

Options

• 0.301

• 130.2

• 212.6

• 176.8

Answer 1

0.301

Explanation:

According to freundlich adsorption 130 there

`log  (x/m) = 10  g  k = 1/n  log  p`

`log  (x/m) = log  (0.4)` = (– 0.398)

`1/n` = tan 45° = 1

log p = log (0.2) = (– 0.990)

(– 0.398) = log k + (1) × (– 0.6900)

log k (interceft) = 0.6990 –  0.398 = 0.301