Question

In the given figure, the block of mass m is dropped from point 'A'. The expression for the kinetic energy of the block when it reaches point 'B' is ______.

  

Options

• `1/2mgy_0^2`

• `1/2mgy^2`

• mg(y - y₀)

• mgy₀

Answer 1

In the given figure, the block of mass m is dropped from point 'A'. The expression for the kinetic energy of the block when it reaches point 'B' is mgy₀.

Explanation:

According to the law of energy conservation, loss in potential energy = gain in kinetic energy

Hence, –(mg (y – y₀) – mgy) = KE – 0

⇒ KE = mgy₀